Question

(a + b)/(2ab) * (a + b - c) + (b + c)/(2bc) * (b + c - a) + (c + a)/(2ca) * (c + a - b)​

Answer 1

Answer:

Answer:

The length of other side of the rectangle is \dfrac{(5x+6)(x-1)}{3x+2}

3x+2

(5x+6)(x−1)

Step-by-step explanation:

The area of rectangle with length ll and breadth bb is,

Area = l \times bArea=l×b

Given that,

\begin{gathered}one side (length)= 3x+2\\\\Area = 5x^2+x-6\end{gathered}

oneside(length)=3x+2

Area=5x

2

+x−6

Substitute these values in the formula for area.

\begin{gathered}5x^2+x-6 =(3x+2) \times b\\\\\implies b =\dfrac{5x^2+x-6}{3x+2}\\\\b= \dfrac{(5x+6)(x-1)}{3x+2}\end{gathered}

5x

2

+x−6=(3x+2)×b

⟹b=

3x+2

5x

2

+x−6

b=

3x+2

(5x+6)(x−1)

Since there is no common factors, we cannot simplify it further.