Math, asked by dvngtrip85, 10 months ago

a =b^2x b=c^2y c=a^2z Find x*y*z

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Answered by tamilarasan14042001
1

Answer:

Answer:

log a = 2x log b

log b = 2y log c

log c = 2z log a

multiply all these

(log a)(log b)(log c) = 8xyz (log a)(log b)(log c)

8 xyz =1

xyz = 1/8

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