Question

(a+b) 2x2+8 (a2-b2) x +16(a-b)2=0

Answer 1

4a+4b+16a-16b+32a+32b=0
52a-44b=0
52a=44b
If solve equation for a, a=(11/13)b
If solve equation for b, b=(13/11)a

Answer 2

Answer:

4(b-a)/a+b

Step-by-step explanation:

a= (a+b)^2    b=-2(a^2-b^2)         c=16(a-b)^2

D = b2- 4ac

here, D = 64(a2 - b2)2 - 4(a+b)2*16(a - b)2

= 64(a4 +b4 -2a2b2) - 64(a4 + a2b2- 2a3b + a2b2 +b4 -2ab3 +2a3b +2ab3-4a2b2)

=64 (a4 +b4- 2a2b2 - a4 -b4 + 2a2b2 )

=0

since D= 0 roots are real and equal

X = (-b +√D)/2a

now you know the values of a, b & D you can find X

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