Math, asked by Ashu1250, 1 year ago

(a+b)²x²+8(a²-b²)x+16(a-b)I=0

Answers

Answered by Anonymous
9
Hello friend
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Given
(a+b)²x²+8(a²-b²)x+16(a-b)=0 [(a+b)x]² + 2*(a+b)x*4(a-b) +[4(a-b)]²

Now this is in the form of (a+b)²= a²+2ab+b²

[(a+b)x + 4(a-b)]² = 0
(a+b)x = -4(a-b)                                                  ∴ √0 = 0
x= -4(a-b)/(a+b)

(or)
x= 4(b-a)/(a+b)
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i hope it's help u :))





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