(a+b)²x²-(a+b)x-6=0
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Hi friend!!
Given, (a+b)²x²-(a+b)x-6=0
→(a+b)²x²-3(a+b)x+2(a+b)x-6=0
→(a+b)x[ax+bx-3]+2[ax+bx-3]=0
→[ax+bx+2][ax+bx-3]=0
→(a+b)x+2=0 or (a+b)x-3=0
→x=-2/(a+b) or 3/(a+b)
I hope this will help you ;)
DhanyaDA:
thank u ^_^
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