Math, asked by divyabathula2612, 11 months ago

A:B=3/5:5/7, B:C=3/4:2/5 then find A:B:C? ​

Answers

Answered by niharikam54
0

Answer:

case -1 :

A:B = 3/5:5/7 A/B = 3/5 / 5/7 we get

A/B = 21/25 ....(1)

case -2:

B:C =3/4:2/5 B/C = 3/4 / 2/5 we get

B/C = 15/8........(2)

Multiplying (1) and (2)

we get A/C = 63/40

then A=63C/40

B=15C/8

consider A:B:C

63C/40: 15 C/48:C

WE GET 63:75:5

Answered by Shubham9131
2

Step-by-step explanation:

A:B=3/5:5/7

B:C=3/4:2/5 lets first take the LCM of Both the B i.e., 5/7 and 3/4

= 28(7*4)

multiplying

A:B WITH 4 as 7 multiplied by 4 = 28

then multiplying B:C WITH 7 as 4*7 is 28

A:B=12/20:20/28 (AFTER MULTIPLYING)

B:C=21/28:14/35

THEREFORE A:B:C is equal to 12/20:21/28:14/35

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