Question

A:B=3:5 and B:C=4:5 and if C is 39 more than A then what is the value of B?

Please give explanations. Thank you.

Answer 1

Solution:

It is given that ,

A:B = 3:5

=> 5A = 3B

A= 3B/5----(1)

B:C = 4:5

=> 4C = 5B ----(2)

And

C = A + 39 ----(3)

Put (3) in (2), we get

4(A+39) = 5B

=> 4A + 156 = 5B

=> 4A = 5B -156 ---(4)

Put (1) in (4) , we get

=> 4(3B/5) = 5B-156

=> 12B = 5(5B-156)

=> 12B = 25B - 780

=> 12B - 25B = -780

=> -13B = -780

=> B = (-780)/(-13)

=> B = 60

Therefore,

B = 60

••••

Answer 2

Answer:

The value of B is 60

Step-by-step explanation:

Given:

$A:B=3:5$

$B:C=4:5$

This implies

$A:B:C=12:20:25$

A=12k, B=20k, C=25k (say)

Also,

$C=A+39$

$25k=12k+39$

$13k=+39$

$k=3$

Therefore, B=20(3)=60