(a+b)^3-8(a-b)^3 factorise it plz
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= a³+b³+3ab(a+b)-8[a³-b³-3ab(a-b)] [By using identities of (a-b)³ and (a+b)³]
= a³+b³+3a²b+3ab²-8[a³-b³-3a²b+3ab²]
= a³+b³+3a²b+3ab²-8a³+8b³+24a²b-24ab²
= -7a³+9b³+27a²b-21ab²
Hope this helps......
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