Question

(a+b)^3-8 briefly prove

Answer 1

(a+b)^3-8
=a+b^-5
[a(a+b)^-5]{b(a+b)^-5}
=(a²+ab^-5)(ba+b²^-5)
=a²+ba²+b²^-5. |taking ab and ba common|√

Answer 2

friend your answer is a square plus of ab square plus b square to the power minus 5