Math, asked by poojapithadia1p32m2z, 1 year ago

(a-b)^3 + a^3 + (a+b)^3 = 408

Answers

Answered by Anonymous
3
(a-b)3+a3+(a+b)3=408
a3-b3-3ab(a-b)+a3+a3+b3+3ab(a+b)=408
3a3-3ab(a-b)+3ab(a+b)=408
3a3-3a2b+3ab2+3a2b+3ab2=408
3a3+6ab2=408
a3+2ab2=136
Answered by ayezakhan2
2
=a^2 +a^3+a+b^3 =a^5 +a+b^3=a^6+b^3=a^6b^3
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