Question

(a+b)^3=a^3+b^3+3ab+(a+b) how it is derieved

Answer 1

Hi...☺

Here is your answer...✌

IDENTITY :

(a + b)³ = a³ + b³ + 3ab(a+b)

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Explantation :

(a + b)³ = (a + b) (a + b)²

= (a + b) (a² + b² + 2ab)

= a(a² + b² + 2ab) + b(a² + b² +2ab)

= a³ + ab² + 2a²b + a²b + b³ + 2ab²

= a³ + b³ + 3a²b + 3ab²

= a³ + b³ + 3ab(a+b)