Question

(a+b)³ - (a-b)³ -6b (a²-b²) . How to solve.​

Answer 1

Step-by-step explanation:

We have,

(a+b)³-(a-b)³-6b(a²-b²)

$we \: know \: that \: (a - b) {}^{3} = a {}^{3} + n \\ b {}^{3} + 3a {b }^{2} + 3b {}^{2} a$

Therefore,a³+b³+3a²b+3b²a-a³-b³+3a²