Question

(a+b)^3-(a-b)^3 factorise
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Answer 1

Answer:

we know that , (a+b)³= a³+b³+3ab(a+b) = a³+b³+3a²b+3ab²

and (a-b)³= a³-b³-3ab(a-b) = a³-b³-3a²b+3ab².

Step-by-step explanation:

now (a+b)³-(a-b)³

= a³+b³+3a²b+3ab²-(a³-b³-3a²b+3ab²)

= a³+b³+3a²b+3ab²-a³+b³+3a²b-3ab²

a³-a³+b³+b³+3a²b+3a²b+3ab²-3ab²

=2b³+6a²b

=2b(b²+3a²)