(a+b)^3+ (a-b)^3 factorise the question.... step by step...
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Answer:
2a(a^2+3b^2)
Step-by-step explanation:
We will write the equation by putting the formulas of both, then we will get
a^3+b^3+3ab(a+b) + a^3-b^3-3ab(a-b)
Then, we will open the brackets
a^3+b^3+3a^2b+3ab^2 + a^3-b^3-3a^2b+3ab^2
Now, after cancelling b^3 and 3a^2b
We get,
2a^3+6ab^2
We get the answer i.e. 2a(a^2+3b^2)
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