Question

(a+b)³+(a-b)³ what is the formula of this

Answer 1

Step-by-step explanation:

a³+3a²b+3ab²+b³+a³-3a²b+3ab²-b³

=2a³+2.3ab²

=2a(a²+3b²)

Answer 2

Step-by-step explanation:

a²+b²+2ab=(a+b)²

a²+b²-2ab=(a-b)²

a²-b²=(a+b)(a-b)

a³+b³=(a+b)(a²+b²-ab)

a³-b³=(a-b)(a²+b²+ab)

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)

a³+b³+3ab(a+b)=(a+b)³

a³-b³-3ab(a-b)=(a-b)³

SO

(a+b)³+(a-b)³

=a³+b³+3ab(a+b)+a³-b³-3ab(a-b)

=2a³+6ab²