Question

a-b=3,a×b=40,a^2+b^2=?
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Answer 1

Answer:

Step-by-step explanation:

Given that,

a- b = 3 and ab = 40

a²+ b² = ( a - b )² + 2ab

= ( 3 )² + 2 ( 40 )

= 9 + 80

= 89 is the answer.

Answer 2

Answer:

Value of $a^{2}+ b^{2}$ is $89$ .

Step-by-step explanation:

To find : value of $a^{2}+ b^{2}$ .

Given : $a- b= 3$ and $a\times b= 40$ .

Solution :

• As per given data we know that ,  $a- b= 3$ and $a\times b= 40$ . We have to find the value of $a^{2}+ b^{2}$ .  
• We apply identity , $(a-b )^{2} = a^{2} -2ab + b^{2}$ .
• Substituting given values in above identity , we find the value of $a^{2}+ b^{2}$
• After substituting values we perform arithmetic operation such as , multiplication and addition to find the value of $a^{2}+ b^{2}$  .

     $(a-b )^{2} = a^{2} -2ab + b^{2} \\\\ (3)^{2} = a^{2} -2(40 ) + b^{2} \\\\9 = a^{2} -80 + b^{2} \\\\a^{2} +b^{2} = 9 + 80 \\\\a^{2} +b^{2} = 89$