(a+b)^3-a-b factories
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( a + b )³ - a - b = ( a + b )³ - ( a + b )
By taking ( a + b ) as common,
= ( a + b ) { ( a + b )² - 1 }
= ( a + b ) ( a² + b² + 2 ab - 1 )
[ ( a + b )² = a² + b² + 2 ab ]
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Answer:
Too easy !
(a + b )³ - ( a + b)
( a + b ) { ( a + b ) ² -1 }
(a + b ) ( a + b +1 ) ( a + b -1 )
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