(a+b)^3-a-b factorise
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(a+b)³ - a - b
(a+b)³ -1(a+b)
(a+b)[(a+b)² - 1]
(a+b)[(a+b)² - (1)²]
(a+b)(a+b+1)(a+b - 1). {using the identity of (a² - b²)}
Anishshaw:
thanks a lot
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