Question

(a+b)^3-a-b what is the factorise of this question​

Answer 1

→ Answer :

( a + b ) ( a + b + 1 ) ( a + b - 1 )

→ Step-by-step explanation :

$(a+b)^3-a-b\\\\=>(a+b)^3-(a+b)\\\\=>(a+b)[(a+b)^2-1)]$

Now it is in form  $a^2-b^2$ so $a^2-b^2$ = $(a+b)(a-b)$

$=>(a+b)[(a+b)^2-1^2]\\\\=>(a+b)([(a+b)+1][(a+b)-1])\\\\=>(a+b)(a+b+1)(a+b-1)$

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