(a+b)³=a³+ b³+3ab(a+b)
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Answer:
To prove: (a+b)³=a³+ b³+3ab(a+b)
Proof:
(a+b)³=(a+b)(a+b)²
=(a+b)(a²+b²+2ab)
=a(a²+b²+2ab)+b(a²+b²+2ab)
=a³+b²a+2a²b+a²b+b³+2ab²
=a³+3a²b+3ab²+b³
=a³+b³+3ab(a+b)
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