(a+b)³-a³-b³
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Answer:
How can I simplify (a+b) ³-a³-b³?
(a+b)^3
= (a+b)(a+b)^2
= (a+b)(a^2+2ab+b^2)
= a^3+2a^2b+ab^2+ba^2+2ab^2+b^3
= (a^3+b^3 + 3a^2b + 3ab^2) _________(1)
now,
(a+b) ³-a³-b³
= a^3+b^3 + 3a^2b + 3ab^2 - a^3 -b^3 [from (1)]
= 3a^2b + 3ab^2
= 3ab(a+b)
Answered by
1
(a+b)^3
= (a+b)(a+b)^2
= (a+b)(a^2+2ab+b^2)
= a^3+2a^2b+ab^2+ba^2+2ab^2+b^3
= (a^3+b^3 + 3a^2b + 3ab^2) _________(1)
now,
(a+b) ³-a³-b³
= a^3+b^3 + 3a^2b + 3ab^2 - a^3 -b^3 [from (1)]
= 3a^2b + 3ab^2
= 3ab(a+b)
Hope it will help u :)
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