Question

a+b=-3 , ab=2 then find a-b?​

Answer 1

Answer:

(a-b)^2=(a+b)^2-4ab

=3^2-4*2

=9-8

=1

a-b=1

Answer 2

$\tt\huge\purple{hello!!!}$

HERE IS UR ANSWER

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$a + b = - 3 ..i\\ ab = 2 ..ii$

$(a-b){}^{2}={a+b}^{2}-4ab\\={-3}^{2}-4(2)\\=9-8=1$

$a-b{}^{2}=1\\a-b=1$