a+b-3 + b-a+3 + a-b+3 please solve it
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Answered by
3
Given (a+b)3−a3−b3
= (a3+3a2b+3ab2+b3)−a3−b3
= a3+3a2b+3ab2+b3−a3−b3
= 3a2b+3ab2
= 3ab(a+b)
Answered by
0
Answer:
The answer for the sum is
Step-by-step explanation:
3ab(a+b)
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