(a - b) ³ + (b - c)³ + (c - a )³
Answers
Answered by
0
We know that
(a-b) ^3=a^3-b^3+3ab(a-b)
Apply this identity and open brackets then you will get the answer
Answered by
0
hey !!!
find here
(a - b) ³ + (b - c)³ + (c - a)³=?
we know that
(x³-y³)=x³-y³-3x²y+3xy²
so,
(a - b) ³ + (b - c)³ + (c - a)³
= a³-b³-3a²b+3ab²+b³-c³-3b²c+3bc²+c³-a³-3c²a+3ca²
=(a³-a³)+(b³-b³)+(c³-c³)+3(-a²b+ab²-b²c+bc²-c²a+ca²)
=3(-a²b+ab²-b²c+bc²-c²a+ca²)
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