Math, asked by swarajrao, 10 months ago

(a - b) ³ + (b - c)³ + (c - a )³

Answers

Answered by goyalsushma446
0

We know that

(a-b) ^3=a^3-b^3+3ab(a-b)

Apply this identity and open brackets then you will get the answer

Answered by Anonymous
0

hey !!!

find here

(a - b) ³ + (b - c)³ + (c - a)³=?

we know that

(x³-y³)=-y³-3x²y+3xy²

so,

(a - b) ³ + (b - c)³ + (c - a)³

= a³-b³-3a²b+3ab²+b³-c³-3b²c+3bc²+-a³-3c²a+3ca²

=(a³-a³)+(b³-b³)+(c³-c³)+3(-a²b+ab²-b²c+bc²-c²a+ca²)

=3(-a²b+ab²-b²c+bc²-c²a+ca²)

I hopes its helps u

please follow me..

@Abhi.

Similar questions