( a-b)^3+(b-c)^3+(c-a)^3
Answers
Answered by
2
Answer:
Step-by-step explanation:
a^3-b^3-3a^b+3ab^2+b^3-c^3-3b^c+3bc^2+c^3-a^3-3c^2a+3a^2c
=3ab^2-3a^2b+3bc^2-3b^2c+3a^2c-3ac^2
=3ab(a-b)+3bc(b-c)+3ac(a-c)
Answered by
0
Answer:
3(b²a+c²b+a²c)
Step-by-step explanation:
as (x-y)^3 = x³-y³-3x²y+3xy²
therefore
a³-b³-3a²b+3ab²+b³-c³-3b²c+3c²b+c³-a³-3c²a+3ca²
3(b²a+c²b+a²c)
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