(a - b) ^ 3 + (b - c) ^ 3 + (c - a) ^ 3
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Answer:
3a2(c−b)+3b2(a−c)+3c2(b−a)
Step-by-step explanation:
(a−b)3+(b−c)3+(c−a)3
=(a3−3a2b+3ab2−b3)+(b3−3b2c+3bc2−c3)+(c3−3c2a+3ca2−a3)
=−3a2b+3ab2−3b2c+3bc2−3c2a+3ca2
=3a2(c−b)+3b2(a−c)+3c2(b−a)
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