(a+b)³ + (b+c)³ + (c+a )³ -3 (a+b)(b+c) (c+a)=2(a³+b³+c³) prove it.
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Answer:
(a+b)³ + (b+c)³ + (c+a )³ -3 (a+b)(b+c) (c+a)=2(a³+b³+c³) prove it.
answer me fast .
please donot spam.
please
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Explanation:
a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca). a³+b³+3ab(a+b)=(a+b)³. a³-b³-3ab(a-b)=(a-b)³
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