(a+b)³ + (b+c)³ + (c+a )³ -3 (a+b)(b+c) (c+a)=2(a³+b³+c³) prove it.
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Step-by-step explanation:
Answer
Step-by-step explanation:
a²+b²+2ab=(a+b)² a²+b²-2ab=(a-b)²
a²-b²=(a+b)(a-b)
a³+b³-(a+b)(a²+b²-ab)
a³-b³=(a-b)(a²+b²+ab) a³+b³+c³-3abc-(a+b+c)
(a²+b²+c²-ab-bc-ca)
a³+b³+3ab(a+b)=(a+b)³ a³-b³-3ab(a-b)=(a-b)³
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