Math, asked by bhupinderku, 8 months ago

(a/b)^3 + (b/c)^3 + (c/a)^3 -3 factorize

Answers

Answered by OkuraZeus
1

Answer:

(a/b)^3 + (b/c)^3 + (c/a)^3 - 3

= (a/b + b/c + c/a)((a/b)^2 + (b/c)^2 + (c/a)^2 - (a/b × b/c) - (b/c × c/a) - (c/a × a/b)

= (a/b + b/c + c/a)((a/b)^2 + (b/c)^2 + (c/a)^2 - (a/c) - (b/a) - (c/b))

Answered by duttatrisha691
0

Answer:

=(a/b+b/c+c/a) {(a/b)^2(b/c)^2(c/a)^2-a/b-b/c-c/a}

=(abc/bca) {(abc^2/bca^2 -abc/bca}

=0

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