(a-b) ³+(b-c)³+(c-a)³ factorize
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We know that if x+y+z = 0
then x³+y³+z³=3xyz
let (a-b) be x
(b-c) be y
(c-a) be z
x+y+z
= a-b+b-c+c-a
= 0
so value of x³+y³+z³ is 3xyz
putting the value of x , y and z
so , answer is 3(a-b)(b-c)(c-a)
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