Math, asked by sushantodey765, 1 month ago

A+B = 30°+ A+B = 60°=​

Answers

Answered by aryanmishr512
0

Answer:

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Step-by-step explanation:

Given in Δ ABC, ∠A=30

o

,∠B=60

o

.

Then ∠C=90

o

.

Now from sine rule of triangle we get,

a=2RsinA, b=2RsinB and c=2RsinC. [ Where R is the radius of the circum-circle of ΔABC.]

Then

a:b:c

=sinA:sinB:sinC

=sin30

o

:sin60

o

:sin90

o

=

2

1

:

2

3

:1

=1:

3

:2.

Answered by NamanSheoran
1

Answer:

a+b=60 -eq.1

a-b=30 -eq.2

less the eq.2 from eq.1

a+b=60

a-b =30

2b=30

b=15

on putting the value of b in eq.1

a+15=60

a=60-15

a=45

so the answer is a=45 & b =15

..hope it helps you...

Please mark It As Brainliest

Step-by-step explanation:

a+b=60 -eq.1

a-b=30 -eq.2

less the eq.2 from eq.1

a+b=60

a-b =30

2b=30

b=15

on putting the value of b in eq.1

a+15=60

a=60-15

a=45

so the answer is a=45 & b =15

..hope it helps you...

Please mark It As Brainliest

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