A+B = 30°+ A+B = 60°=
Answers
Answered by
0
Answer:
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Step-by-step explanation:
Given in Δ ABC, ∠A=30
o
,∠B=60
o
.
Then ∠C=90
o
.
Now from sine rule of triangle we get,
a=2RsinA, b=2RsinB and c=2RsinC. [ Where R is the radius of the circum-circle of ΔABC.]
Then
a:b:c
=sinA:sinB:sinC
=sin30
o
:sin60
o
:sin90
o
=
2
1
:
2
3
:1
=1:
3
:2.
Answered by
1
Answer:
a+b=60 -eq.1
a-b=30 -eq.2
less the eq.2 from eq.1
a+b=60
a-b =30
2b=30
b=15
on putting the value of b in eq.1
a+15=60
a=60-15
a=45
so the answer is a=45 & b =15
..hope it helps you...
Please mark It As Brainliest
Step-by-step explanation:
a+b=60 -eq.1
a-b=30 -eq.2
less the eq.2 from eq.1
a+b=60
a-b =30
2b=30
b=15
on putting the value of b in eq.1
a+15=60
a=60-15
a=45
so the answer is a=45 & b =15
..hope it helps you...
Please mark It As Brainliest
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