Question

A+B=300°then(1+√3cotA)(1+√3cot B)​

Answer 1

Answer:

Step-by-step explanation:

A + B=300

A +B=(360-60)

multiply cot on both sides  

cot(A + B) =cot(360-60)

cotAcotB-1/cotA +cotB=–cot60

cotAcotB-1/cotA+cotB=–1/root3

root3cotAcotB-root3=–cotA–cotB

root3cotAcotB+cotA+cotB=root3

cotA(1+root3cotB)+cotB=root3

Multiply root3 on both sides  

root3cotA(1+root3cotB)+cotA=(root3)(root3)

(1+root3cotA)(1+root3cotB)=3

Answer 2

in this picture there is your answer