Question

a/b=4/3to find a(3a+2b)/(3a-2b)

Answer 1

this is the solution of your question.

Answer 2

Hey dear user!
Here is the your Answer

$\frac{a}{b} = \frac{4}{3} \\ now \: let \: common \: b \\ \frac{(3a + 2b)}{(3a - 2b)} = \frac{(3 \frac{a}{b} + 2 )}{(3 \frac{a}{b} - 2)} \\ = putting \: the \: value \\ \\ = \frac{3 \frac{4}{3} + 2}{3 \frac{4}{3} - 2} = \frac{4 + 2}{4 - 2 } \\ \\ = \frac{6}{2} = 3$