Question

A-b= 4 5 b-a= 6 7 8 and a intersection b= 2 3 find n a union b

Answer 1

hey

n(a-b) + n (b-a) - n(a intersection b) = n(aUb)
n(aUb) = 2 + 3 - 2
= 5 - 2
= 3

Answer 2

Answer:

3

Step-by-step explanation:

a - b = {4, 5}

b - a = {6, 7, 8} and

a ∩ b = {2, 3}

To find:

n(a ∪ b)

n(a ∪ b) = n(a - b) + n(b - a) - n(a ∩ b)

n(a ∪ b) = 2 + 3 - 2

= 5 - 2

= 3

@Pavan

$\sf\huge{\blue{Hope it helps you }}$