Math, asked by nikhilgupta0716, 2 months ago

a-b=4 a^2+b^2=40 a^3-b^3=? ab=?

Answers

Answered by jitendertypist702
0

Step-by-step explanation:

Given,

a-b=4

a²+b²=40

To Find,

a³-b³=?

ab=?

Here,

1). (a-b)²=a²+b²-2ab

(a-b)²+2ab=a²+b²

(4)²+2ab=40

16+2ab=40

2ab=40-16

2ab=24

ab=24/2

ab=12

* (a+b)²=a²+b²+2ab

(a+b)²=40+2(12)

(a+b)²=40+24

(a+b)²=64

a+b=8

2). a³-b³=(a-b)(a²+b²+ab)

=(4)(40+12)

=4×52

=208

Hope it will help you..

Answered by snigdhachakraborty19
0

Answer:

12,8,208

Step-by-step explanation:

Please marke as a brainliest

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