Math, asked by anshkohli8076, 6 months ago

a-b=4, a^3-b^3=88, a^2+b^2+ab=? Please Help​

Answers

Answered by adii99
1

Answer:

22

Step-by-step explanation:

a^3 -b^3 = (a-b) (a^2 + ab +b^2)

put the values given

88 = 4 ( a^2 + ab +b^2)

a^2 + ab +b^2 = 88 ÷ 4

a^2 + ab +b^2 = 22

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