A + B = 4, AB = 2, find the value of A^5 + B^5."IT'S A JEE ADVANCE QUESTION"
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Answer:
Step-by-step explanation:
A + B = 4
ON SQ
A^2 + B^2 = (A+ B)^2 - 2 AB
= 12
ON CUBEING BOTH SIDE
A^5 +B^5 = (A^2 + B^2)^3 - 3*A^2*B^2(A^2 + B^2)
= 1728 - (3*4(12)
= 1728 - 144
1584
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