Math, asked by rashmisinha14, 1 year ago

a_b=4,ab=21,find a3_b3 ​

Answers

Answered by Anonymous
1

Answer:

Ans is 316

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Step-by-step explanation:

a-b=4

ab=21

a^2+b^2=(a-b)^2+2ab=4^2+2*21=16+42=58

Now....

a^3-b^3=(a-b)(a^2+b^2+ab)

=(4) (58+21)

=4*79

=316

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