a_b=4,ab=21,find a3_b3
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Answer:
Ans is 316
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Step-by-step explanation:
a-b=4
ab=21
a^2+b^2=(a-b)^2+2ab=4^2+2*21=16+42=58
Now....
a^3-b^3=(a-b)(a^2+b^2+ab)
=(4) (58+21)
=4*79
=316
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