A-B=45° and tanA-tanB=√3 then tanA*tanB
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tan45°=√3/(1+tanAtanB)
(1+tanAtanB)= √3/(tan45°)
(1+tanAtanB)=√3/(1)
tanAtanB=√3-1
(1+tanAtanB)= √3/(tan45°)
(1+tanAtanB)=√3/(1)
tanAtanB=√3-1
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this is the answer.i hope u understood and help you
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