Question

a+b = 5; a^2+b^2=13, value of a-b=? where a>b

Answer 1

(a + b )^2 = a2 + b2 + 2ab

25 = 13 + 2 ab

ab = 6

(a - b )^2 = a2 + b2 - 2ab

= 13 - 12 = 1

(a - b ) = +1 and -1

when a>b so (a - b ) = 1

hope it helps..

Answer 2

Answer:

(a-b)=1

Hope it helps

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