a+b = √5 , a-b=√3 then (a²+b²)?
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Step-by-step explanation:
SOLUTION
GIVEN
a + b = 5 & a - b = 3
TO DETERMINE
The value of a² - b²
FORMULA TO BE IMPLEMENTED
We are aware of the identity that
\sf{ {a}^{2} - {b}^{2} = (a + b)(a - b) }a2−b2=(a+b)(a−b)
EVALUATION
Here it is given that a + b = 5 & a - b = 3
Now
\sf{ {a}^{2} - {b}^{2} }a2−b2
\sf{ = (a + b)(a - b) }=(a+b)(a−b)
\sf{ = 5 \times 3 }=5×3
\sf{ = 15 }=15
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