Question

A+b=5, ab=3 then find the equation whose zeros are 1/a^2 , 1/b^2

Answer 1

Answer:

x² - (sum of zeroes)x + product of zeroes

x² - (1/a + 1/b )x + 1/a × 1/b

x² - ((b+a)/ab)x + 1/ab

{x}^{2} - \frac{b + a}{ab} x + \frac{1}{ab}