a+b=5 and a-6=3, fond (a ²+b²) = ?
Answers
Answered by
3
Answer:
Here,
a = 5 + 2√6
b = 1/a
=1/( 5 + 2√6)
=(5 -2√6)/(5+2√6)(5 -2√6)
=(5 -2√6)/{5² -(2√6)²}
=(5 -2√6)/(25 -24)
=5 -2√6
now,
a² + b² = (a + b)² -2ab
=(5 +2√6 +5 -2√6)² -2(5 +2√6)(5 -2√6)
=(10)² -2(25 -24)
=100 -2
= 98
hence, a² + b² = 98
Answered by
0
Answer:
Step-by-step explanation:
a+b=5
a-b=3
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2a=8
a=4
b=1
a^2+b^2=16+1=17
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