a+b = 6 a*b = 6 find a and b
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Step-by-step explanation:
Thevalueofa2+b2=26
Step-by-step explanation:
Given
a-b = 4
=> a = 4+b ----(1)
and
a+b=6 ----(2)
Substitute (1) in equation (2), we get
=> 4+b+b=6
=> 4+2b=6
=> 2b=6-4
=> 2b=2
\implies b = \frac{2}{2}⟹b=22
\implies b = 1⟹b=1
Now ,
put b = 1 in equation (1), we get
a=4+1
=> a = 5
\begin{lgathered}Value\: of\: a^{2}+b^{2}\\=5^{2}+1^{2}\\=25+1\\=26\end{lgathered}Valueofa2+b2=52+12=25+1=26
Therefore,
The\: value\:of \:a^{2}+b^{2}=26Thevalueofa2+b2=26
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