Math, asked by nehasingh5792061, 3 months ago

a-b=6 and a^2-b^2=222 then the value of a^3-b^3 is

Answers

Answered by sugandh9379
0

Answer:

I not understand your question

Answered by rkcomp31
1

a³-b³=6214.5

Step-by-step explanation:

a-b=6 ---------(1)

and a^2-b^2=222

(a+b)(a-b)=222

(a+b)*6=222

a+b=222/6=37------(2)

form (1) and (2) we get

a=21.5 and 15.5

Now a³-b³=(a-b)(a²+b²+ab)

=(a-b)(a²+b²+2ab-ab)

=6*{ (a+b)²-ab}

=6*{ 37²-15.5*21.5}

=6*( 1369-333.25)

=6214.5

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