a+b=60
ab=800
find a,b
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Hi there
Your answer is :-
a + b = 60
a × b = 800
a = 60 - b
Putting the value a = 60 - b
we get,
a × b = 800
( 60 - b ) × b = 800
60b - b^2 = 800
b^2 = 800 + 60 b
b^2 - 60b + 800 = 0
b^2 - 40b - 20b + 800
b ( b - 40 ) - 20 ( b - 40 )
( b - 40 ) ( b - 20 )
b = 20 , 40
Putting value b = 20
a + 20 = 60
a = 60 - 20
a = 40
( a × b = 800 )
( 40 × 20 = 800 )
Putting value b = 40
a + 40 = 60
a = 60 - 40
a = 20
( a × b = 800 )
( 20 × 40 = 800 )
Therefore ,
a = 40 or 20
b = 20 or 40 ( Ans )
Thank You
Your answer is :-
a + b = 60
a × b = 800
a = 60 - b
Putting the value a = 60 - b
we get,
a × b = 800
( 60 - b ) × b = 800
60b - b^2 = 800
b^2 = 800 + 60 b
b^2 - 60b + 800 = 0
b^2 - 40b - 20b + 800
b ( b - 40 ) - 20 ( b - 40 )
( b - 40 ) ( b - 20 )
b = 20 , 40
Putting value b = 20
a + 20 = 60
a = 60 - 20
a = 40
( a × b = 800 )
( 40 × 20 = 800 )
Putting value b = 40
a + 40 = 60
a = 60 - 40
a = 20
( a × b = 800 )
( 20 × 40 = 800 )
Therefore ,
a = 40 or 20
b = 20 or 40 ( Ans )
Thank You
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