A=B=60 then show
cos[A-B]=CosACosB+ SinASinB
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shivkumar3379:
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ANSWER :
LHS = cos ( A - B )
= cos ( 60 - 60)
= cos (0)
= cos 0
= 1
RHS =
cos A=cos 60 = 1/2
cos B=cos 60 = 1/2
SinA= sin 60 = √3/2
SinB= sin 60 = √3/2
Putting the values,
=> [ (1/2)(1/2) + (√3/2) (√3/2) ]
=> [ (1/4) + (3/4) ]
=> [ (1+3)/4 ]
=> [ 4/4 ]
=> 1
=>LHS
=>HENCE PROVED
HOPE IT HELPS
☜☆☞
LHS = cos ( A - B )
= cos ( 60 - 60)
= cos (0)
= cos 0
= 1
RHS =
cos A=cos 60 = 1/2
cos B=cos 60 = 1/2
SinA= sin 60 = √3/2
SinB= sin 60 = √3/2
Putting the values,
=> [ (1/2)(1/2) + (√3/2) (√3/2) ]
=> [ (1/4) + (3/4) ]
=> [ (1+3)/4 ]
=> [ 4/4 ]
=> 1
=>LHS
=>HENCE PROVED
HOPE IT HELPS
☜☆☞
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