/A+B/=√63and /A-B/=√37 and A=
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Given that a=6,b=3 & cos(A−B)=4/5
Solution :- We know that
tan(2A−B)=1+cos(A−B)1−cos(A−B)
=1+4/51−4/5
=5+45−4=91=31
∴tan(2A−B)=31
mow, we know that,
tan(2A−B)=a+ba−bcot2c
31=6+36−3cot2c
cot
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