Question

a/b = 7/3, now find the value of (a³-b³) / b³

Answer 1

a^3=117+b^3

a^3-b^3=117

Applying algebraic identify

(a-b)(a^2+ab+b^2)=117

Given a=3+b

(3+b-b)[(3+b)^2+(3+b)b+b^2]=117

Upon simplification b=-5,2

so a=-2,5

So that a+b=-7,7

(3)(9+6b+b^2+3b+b^2+b^2)=117