Question

(a+b) =7 a^2+b^2=5 find ab​

Answer 1

Answer:

hi!

here is your answer!

we have to use the identity (a+b)^2

(a+b)^2=a^2+b^2+2ab

(7)^2=5+2ab

49=5+2ab

49-5=2ab

44=2ab

44/2=ab

22=ab

hope it helps you!

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Answer 2

Answer-

We are given that,

a+b= 7 --- (1)

a²+b²= 5 --- (2)

1. Taking equation (1),

a+b= 7

2. Squaring both sides,

(a+b)² = 7²

3. Applying the identity [(x+y)²= x²+ y² +2xy where x= a, y=b]

a²+ b²+ 2ab= 49 {∵ 7²= 7×7= 49}

4. Substituting value of a²+ b² which is equal to 5 {from eq. (2)}

⇒ 5 + 2ab= 49

⇒ 2ab= 49-5

⇒ 2ab= 44

⇒ ab= 44÷2

⇒ ab= 22

∴ Value of ab= 22